Whakaoti i te h=1/2gt^2+u_{0}t

$$h = \frac { 1 } { 2 } g t ^ { 2 } + u _ { 0 } t$$

Whakaoti mō g

$$\left\{\begin{matrix}g=-\frac{2\left(tu_{0}-h\right)}{t^{2}}\text{, }&t\neq 0\\g\in \mathrm{R}\text{, }&h=0\text{ and }t=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{1}{2}gt^{2}+u_{0}t=h$$

Tangohia te u_{0}t mai i ngā taha e rua.

$$\frac{1}{2}gt^{2}=h-u_{0}t$$

He hanga arowhānui tō te whārite.

$$\frac{t^{2}}{2}g=h-tu_{0}$$

Whakawehea ngā taha e rua ki te \frac{1}{2}t^{2}.

$$\frac{2\times \frac{t^{2}}{2}g}{t^{2}}=\frac{2\left(h-tu_{0}\right)}{t^{2}}$$

Mā te whakawehe ki te \frac{1}{2}t^{2} ka wetekia te whakareanga ki te \frac{1}{2}t^{2}.

$$g=\frac{2\left(h-tu_{0}\right)}{t^{2}}$$

Whakaoti mō h

$$h=\frac{t\left(gt+2u_{0}\right)}{2}$$