Whakaoti i te h=frac{sqrt{3x}}{2}

$$h = \frac { \sqrt { 3 x } } { 2 }$$

Whakaoti mō x

$$x=\frac{4h^{2}}{3}$$

$$h\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{\sqrt{3x}}{2}=h$$

Me whakarea ngā taha e rua ki te 2.

$$\frac{\frac{1}{2}\sqrt{3x}}{\frac{1}{2}}=\frac{h}{\frac{1}{2}}$$

Mā te whakawehe ki te \frac{1}{2} ka wetekia te whakareanga ki te \frac{1}{2}.

$$\sqrt{3x}=\frac{h}{\frac{1}{2}}$$

Whakawehe h ki te \frac{1}{2} mā te whakarea h ki te tau huripoki o \frac{1}{2}.

$$\sqrt{3x}=2h$$

Pūruatia ngā taha e rua o te whārite.

$$3x=4h^{2}$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3x}{3}=\frac{4h^{2}}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$x=\frac{4h^{2}}{3}$$

Whakaoti mō x (complex solution)

$$x=\frac{4h^{2}}{3}$$

$$|\frac{arg(h^{2})}{2}-arg(h)|<\pi \text{ or }h=0$$

Whakaoti mō h

$$h=\frac{\sqrt{3x}}{2}$$

$$x\geq 0$$