Whakaoti i te g(x)=-x^2-3x

$$g ( x ) = - x ^ { 2 } - 3 x$$

Tauwehe

$$-x\left(x+3\right)$$

Ngā Upane Otinga

Tauwehea te x.

$$x\left(-x-3\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$-x^{2}-3x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te \left(-3\right)^{2}.

$$x=\frac{-\left(-3\right)±3}{2\left(-1\right)}$$

Ko te tauaro o -3 ko 3.

$$x=\frac{3±3}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$x=\frac{3±3}{-2}$$

Nā, me whakaoti te whārite x=\frac{3±3}{-2} ina he tāpiri te ±. Tāpiri 3 ki te 3.

$$x=\frac{6}{-2}$$

Whakawehe 6 ki te -2.

$$x=-3$$

Nā, me whakaoti te whārite x=\frac{3±3}{-2} ina he tango te ±. Tango 3 mai i 3.

$$x=\frac{0}{-2}$$

Whakawehe 0 ki te -2.

$$x=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -3 mō te x_{1} me te 0 mō te x_{2}.

$$-x^{2}-3x=-\left(x-\left(-3\right)\right)x$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$-x^{2}-3x=-\left(x+3\right)x$$

Aromātai

$$-x\left(x+3\right)$$