Whakaoti i te g(x)=x^3+8x/x^2-64divx^2+4x-45/x^2+x-72

$$g ( x ) = \frac { x ^ { 3 } + 8 x } { x ^ { 2 } - 64 } \div \frac { x ^ { 2 } + 4 x - 45 } { x ^ { 2 } + x - 72 }$$

Aromātai

$$\frac{x\left(x^{2}+8\right)}{\left(x-5\right)\left(x+8\right)}$$

Ngā Hipanga Rongoā Poto

Whakawehe \frac{x^{3}+8x}{x^{2}-64} ki te \frac{x^{2}+4x-45}{x^{2}+x-72} mā te whakarea \frac{x^{3}+8x}{x^{2}-64} ki te tau huripoki o \frac{x^{2}+4x-45}{x^{2}+x-72}.

$$\frac{\left(x^{3}+8x\right)\left(x^{2}+x-72\right)}{\left(x^{2}-64\right)\left(x^{2}+4x-45\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{x\left(x-8\right)\left(x+9\right)\left(x^{2}+8\right)}{\left(x-8\right)\left(x-5\right)\left(x+8\right)\left(x+9\right)}$$

Me whakakore tahi te \left(x-8\right)\left(x+9\right) i te taurunga me te tauraro.

$$\frac{x\left(x^{2}+8\right)}{\left(x-5\right)\left(x+8\right)}$$

Me whakaroha te kīanga.

$$\frac{x^{3}+8x}{x^{2}+3x-40}$$

Whakaroha

$$\frac{x^{3}+8x}{\left(x-5\right)\left(x+8\right)}$$

Ngā Hipanga Rongoā Poto

Whakawehe \frac{x^{3}+8x}{x^{2}-64} ki te \frac{x^{2}+4x-45}{x^{2}+x-72} mā te whakarea \frac{x^{3}+8x}{x^{2}-64} ki te tau huripoki o \frac{x^{2}+4x-45}{x^{2}+x-72}.

$$\frac{\left(x^{3}+8x\right)\left(x^{2}+x-72\right)}{\left(x^{2}-64\right)\left(x^{2}+4x-45\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{x\left(x-8\right)\left(x+9\right)\left(x^{2}+8\right)}{\left(x-8\right)\left(x-5\right)\left(x+8\right)\left(x+9\right)}$$

Me whakakore tahi te \left(x-8\right)\left(x+9\right) i te taurunga me te tauraro.

$$\frac{x\left(x^{2}+8\right)}{\left(x-5\right)\left(x+8\right)}$$

Me whakaroha te kīanga.

$$\frac{x^{3}+8x}{x^{2}+3x-40}$$