Whakaoti i te g(x)=x^3+6x/x^2-36divx^2+3x-40/x^2+2x-48

$$g ( x ) = \frac { x ^ { 3 } + 6 x } { x ^ { 2 } - 36 } \div \frac { x ^ { 2 } + 3 x - 40 } { x ^ { 2 } + 2 x - 48 }$$

Aromātai

$$\frac{x\left(x^{2}+6\right)}{\left(x-5\right)\left(x+6\right)}$$

Ngā Hipanga Rongoā Poto

Whakawehe \frac{x^{3}+6x}{x^{2}-36} ki te \frac{x^{2}+3x-40}{x^{2}+2x-48} mā te whakarea \frac{x^{3}+6x}{x^{2}-36} ki te tau huripoki o \frac{x^{2}+3x-40}{x^{2}+2x-48}.

$$\frac{\left(x^{3}+6x\right)\left(x^{2}+2x-48\right)}{\left(x^{2}-36\right)\left(x^{2}+3x-40\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{x\left(x-6\right)\left(x+8\right)\left(x^{2}+6\right)}{\left(x-6\right)\left(x-5\right)\left(x+6\right)\left(x+8\right)}$$

Me whakakore tahi te \left(x-6\right)\left(x+8\right) i te taurunga me te tauraro.

$$\frac{x\left(x^{2}+6\right)}{\left(x-5\right)\left(x+6\right)}$$

Me whakaroha te kīanga.

$$\frac{x^{3}+6x}{x^{2}+x-30}$$

Whakaroha

$$\frac{x^{3}+6x}{\left(x-5\right)\left(x+6\right)}$$

Ngā Hipanga Rongoā Poto

Whakawehe \frac{x^{3}+6x}{x^{2}-36} ki te \frac{x^{2}+3x-40}{x^{2}+2x-48} mā te whakarea \frac{x^{3}+6x}{x^{2}-36} ki te tau huripoki o \frac{x^{2}+3x-40}{x^{2}+2x-48}.

$$\frac{\left(x^{3}+6x\right)\left(x^{2}+2x-48\right)}{\left(x^{2}-36\right)\left(x^{2}+3x-40\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{x\left(x-6\right)\left(x+8\right)\left(x^{2}+6\right)}{\left(x-6\right)\left(x-5\right)\left(x+6\right)\left(x+8\right)}$$

Me whakakore tahi te \left(x-6\right)\left(x+8\right) i te taurunga me te tauraro.

$$\frac{x\left(x^{2}+6\right)}{\left(x-5\right)\left(x+6\right)}$$

Me whakaroha te kīanga.

$$\frac{x^{3}+6x}{x^{2}+x-30}$$