Whakaoti i te g=2/1-r

$$g = \frac { 2 } { 1 - r }$$

Whakaoti mō r

$$r=\frac{g-2}{g}$$

$$g\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe r ki 1 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te -r+1.

$$g\left(-r+1\right)=2$$

Whakamahia te āhuatanga tohatoha hei whakarea te g ki te -r+1.

$$-gr+g=2$$

Tangohia te g mai i ngā taha e rua.

$$-gr=2-g$$

He hanga arowhānui tō te whārite.

$$\left(-g\right)r=2-g$$

Whakawehea ngā taha e rua ki te -g.

$$\frac{\left(-g\right)r}{-g}=\frac{2-g}{-g}$$

Mā te whakawehe ki te -g ka wetekia te whakareanga ki te -g.

$$r=\frac{2-g}{-g}$$

Whakawehe 2-g ki te -g.

$$r=1-\frac{2}{g}$$

Tē taea kia ōrite te tāupe r ki 1.

$$r=1-\frac{2}{g}\text{, }r\neq 1$$

Whakaoti mō g

$$g=\frac{2}{1-r}$$

$$r\neq 1$$