Whakaoti i te fx=x^2-1/2x

$$fx = \frac{ { x }^{ 2 } -1 }{ 2x }$$

Whakaoti mō f

$$f=\frac{1}{2}-\frac{1}{2x^{2}}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2x.

$$fx\times 2x=x^{2}-1$$

Whakareatia te x ki te x, ka x^{2}.

$$fx^{2}\times 2=x^{2}-1$$

He hanga arowhānui tō te whārite.

$$2x^{2}f=x^{2}-1$$

Whakawehea ngā taha e rua ki te 2x^{2}.

$$\frac{2x^{2}f}{2x^{2}}=\frac{x^{2}-1}{2x^{2}}$$

Mā te whakawehe ki te 2x^{2} ka wetekia te whakareanga ki te 2x^{2}.

$$f=\frac{x^{2}-1}{2x^{2}}$$

Whakawehe x^{2}-1 ki te 2x^{2}.

$$f=\frac{1}{2}-\frac{1}{2x^{2}}$$

Whakaoti mō x (complex solution)

$$x=-i\left(2f-1\right)^{-\frac{1}{2}}$$

$$x=i\left(2f-1\right)^{-\frac{1}{2}}\text{, }f\neq \frac{1}{2}$$

Whakaoti mō x

$$x=\sqrt{-\frac{1}{2f-1}}$$

$$x=-\sqrt{-\frac{1}{2f-1}}\text{, }f<\frac{1}{2}$$