Whakaoti mō f
f=x-2+\frac{3}{x}
x\neq 0
Whakaoti mō x (complex solution)
x=\frac{-\sqrt{f^{2}+4f-8}+f+2}{2}
x=\frac{\sqrt{f^{2}+4f-8}+f+2}{2}
Whakaoti mō x
x=\frac{-\sqrt{f^{2}+4f-8}+f+2}{2}
x=\frac{\sqrt{f^{2}+4f-8}+f+2}{2}\text{, }f\geq 2\sqrt{3}-2\text{ or }f\leq -2\sqrt{3}-2
Graph
Tohaina
Kua tāruatia ki te papatopenga
xf=x^{2}-2x+3
He hanga arowhānui tō te whārite.
\frac{xf}{x}=\frac{x^{2}-2x+3}{x}
Whakawehea ngā taha e rua ki te x.
f=\frac{x^{2}-2x+3}{x}
Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.
f=x-2+\frac{3}{x}
Whakawehe x^{2}-2x+3 ki te x.
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