Whakaoti i te ff=5

$$f f = 5$$

Whakaoti mō f

$$f=\sqrt{5}\approx 2.236067977$$

$$f=-\sqrt{5}\approx -2.236067977$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te f ki te f, ka f^{2}.

$$f^{2}=5$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$f=\sqrt{5} f=-\sqrt{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te f ki te f, ka f^{2}.

$$f^{2}=5$$

Tangohia te 5 mai i ngā taha e rua.

$$f^{2}-5=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -5 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$f=\frac{0±\sqrt{0^{2}-4\left(-5\right)}}{2}$$

Pūrua 0.

$$f=\frac{0±\sqrt{-4\left(-5\right)}}{2}$$

Whakareatia -4 ki te -5.

$$f=\frac{0±\sqrt{20}}{2}$$

Tuhia te pūtakerua o te 20.

$$f=\frac{0±2\sqrt{5}}{2}$$

Nā, me whakaoti te whārite f=\frac{0±2\sqrt{5}}{2} ina he tāpiri te ±.

$$f=\sqrt{5}$$

Nā, me whakaoti te whārite f=\frac{0±2\sqrt{5}}{2} ina he tango te ±.

$$f=-\sqrt{5}$$

Kua oti te whārite te whakatau.

$$f=\sqrt{5} f=-\sqrt{5}$$