Whakaoti i te f8x^2-x+2=0

$$f 8 x ^ { 2 } - x + 2 = 0$$

Whakaoti mō f_8

$$f_{8}=\frac{x-2}{x^{2}}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te x ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$f_{8}x^{2}+2=x$$

Tangohia te 2 mai i ngā taha e rua.

$$f_{8}x^{2}=x-2$$

He hanga arowhānui tō te whārite.

$$x^{2}f_{8}=x-2$$

Whakawehea ngā taha e rua ki te x^{2}.

$$\frac{x^{2}f_{8}}{x^{2}}=\frac{x-2}{x^{2}}$$

Mā te whakawehe ki te x^{2} ka wetekia te whakareanga ki te x^{2}.

$$f_{8}=\frac{x-2}{x^{2}}$$

Whakaoti mō x (complex solution)

$$\left\{\begin{matrix}x=\frac{\sqrt{1-8f_{8}}+1}{2f_{8}}\text{; }x=\frac{-\sqrt{1-8f_{8}}+1}{2f_{8}}\text{, }&f_{8}\neq 0\\x=2\text{, }&f_{8}=0\end{matrix}\right.$$

Whakaoti mō x

$$\left\{\begin{matrix}x=\frac{\sqrt{1-8f_{8}}+1}{2f_{8}}\text{; }x=\frac{-\sqrt{1-8f_{8}}+1}{2f_{8}}\text{, }&f_{8}\neq 0\text{ and }f_{8}\leq \frac{1}{8}\\x=2\text{, }&f_{8}=0\end{matrix}\right.$$