Whakaoti i te f(x)^-1=x^3+1/2

$$f ( x ) ^ { - 1 } = \frac { x ^ { 3 } + 1 } { 2 }$$

Whakaoti mō f

$$f=\frac{x\left(x^{3}+1\right)}{2}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2fx^{-1}=x^{3}+1$$

Whakaraupapatia anō ngā kīanga tau.

$$2\times \frac{1}{x}f=x^{3}+1$$

Whakareatia ngā taha e rua o te whārite ki te x.

$$2\times 1f=xx^{3}+x$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1 me te 3 kia riro ai te 4.

$$2\times 1f=x^{4}+x$$

Whakareatia te 2 ki te 1, ka 2.

$$2f=x^{4}+x$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2f}{2}=\frac{x^{4}+x}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$f=\frac{x^{4}+x}{2}$$