Whakaoti i te f(x)=x^2-3xyg(x)=-x^2+5x

$$f ( x ) = x ^ { 2 } - 3 x y g ( x ) = - x ^ { 2 } + 5 x$$

Whakaoti mō g

$$\left\{\begin{matrix}g=\frac{2x-5}{3xy}\text{, }&y\neq 0\text{ and }x\neq 0\\g\in \mathrm{R}\text{, }&x=0\text{ or }\left(x=\frac{5}{2}\text{ and }y=0\right)\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}-3x^{2}yg=-x^{2}+5x$$

Tangohia te x^{2} mai i ngā taha e rua.

$$-3x^{2}yg=-x^{2}+5x-x^{2}$$

Pahekotia te -x^{2} me -x^{2}, ka -2x^{2}.

$$-3x^{2}yg=-2x^{2}+5x$$

He hanga arowhānui tō te whārite.

$$\left(-3yx^{2}\right)g=5x-2x^{2}$$

Whakawehea ngā taha e rua ki te -3x^{2}y.

$$\frac{\left(-3yx^{2}\right)g}{-3yx^{2}}=\frac{x\left(5-2x\right)}{-3yx^{2}}$$

Mā te whakawehe ki te -3x^{2}y ka wetekia te whakareanga ki te -3x^{2}y.

$$g=\frac{x\left(5-2x\right)}{-3yx^{2}}$$

Whakawehe x\left(5-2x\right) ki te -3x^{2}y.

$$g=-\frac{5-2x}{3xy}$$

Whakaoti mō x

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x=\frac{5}{2-3gy}\text{, }&g=0\text{ or }y\neq \frac{2}{3g}\end{matrix}\right.$$