Whakaoti i te f(x)=3x^3-1/2x^2+3/x^3.1=10

$$f ( x ) = 3 x ^ { 3 } - \frac { 1 } { 2 x ^ { 2 } } + \frac { 3 } { x ^ { 3 } } . 1 = 10$$

Aromātai

$$3x^{3}-\frac{1}{2x^{2}}+\frac{3}{x^{3}}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 3x^{3} ki te \frac{2x^{2}}{2x^{2}}.

$$\frac{3x^{3}\times 2x^{2}}{2x^{2}}-\frac{1}{2x^{2}}+\frac{3}{x^{3}}$$

Tā te mea he rite te tauraro o \frac{3x^{3}\times 2x^{2}}{2x^{2}} me \frac{1}{2x^{2}}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3x^{3}\times 2x^{2}-1}{2x^{2}}+\frac{3}{x^{3}}$$

Mahia ngā whakarea i roto o 3x^{3}\times 2x^{2}-1.

$$\frac{6x^{5}-1}{2x^{2}}+\frac{3}{x^{3}}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 2x^{2} me x^{3} ko 2x^{3}. Whakareatia \frac{6x^{5}-1}{2x^{2}} ki te \frac{x}{x}. Whakareatia \frac{3}{x^{3}} ki te \frac{2}{2}.

$$\frac{\left(6x^{5}-1\right)x}{2x^{3}}+\frac{3\times 2}{2x^{3}}$$

Tā te mea he rite te tauraro o \frac{\left(6x^{5}-1\right)x}{2x^{3}} me \frac{3\times 2}{2x^{3}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(6x^{5}-1\right)x+3\times 2}{2x^{3}}$$

Mahia ngā whakarea i roto o \left(6x^{5}-1\right)x+3\times 2.

$$\frac{6x^{6}-x+6}{2x^{3}}$$

Tauwehe

$$\frac{6x^{6}-x+6}{2x^{3}}$$