Whakaoti i te f(x)=2a^3-a^2-7a+6

Tauwehe

Aromātai

Pātaitai

Polynomial

5 raruraru e ōrite ana ki:

Ngā Raru Ōrite mai i te Rapu Tukutuku

https://socratic.org/questions/how-do-you-find-all-the-zeros-of-f-x-2x-3-x-2-3x-1

https://socratic.org/questions/what-is-the-equation-of-the-normal-line-of-f-x-2x-3-x-2-3x-9-at-x-1

https://socratic.org/questions/how-do-you-find-the-local-extrema-for-f-x-2x-3-x-2-4x-3

https://socratic.org/questions/how-do-you-evaluate-the-function-f-x-2x-3-x-2-4x-9-for-x-3

https://socratic.org/questions/how-do-you-determine-if-rolles-theorem-can-be-applied-to-f-x-2x-3-x-2-8x-4-on-th

https://socratic.org/questions/how-do-you-find-the-exact-relative-maximum-and-minimum-of-the-polynomial-functio-24

Tohaina

Kua tāruatia ki te papatopenga

\left(2a-3\right)\left(a^{2}+a-2\right)

Tā te Rational Root Theorem, ko ngā pūtake whakahau katoa o tētahi pūrau kei te āhua o \frac{p}{q}, ina wehea e p te kīanga pūmau 6, ā, ka wehea e q te whakarea arahanga 2. Ko tetahi pūtake pērā ko \frac{3}{2}. Tauwehea te pūrau mā te whakawehe mā te 2a-3.

p+q=1 pq=1\left(-2\right)=-2

Whakaarohia te a^{2}+a-2. Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei a^{2}+pa+qa-2. Hei kimi p me q, whakaritea tētahi pūnaha kia whakaoti.

p=-1 q=2

I te mea kua tōraro te pq, he tauaro ngā tohu o p me q. I te mea kua tōrunga te p+q, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Ko te takirua anake pērā ko te otinga pūnaha.

\left(a^{2}-a\right)+\left(2a-2\right)

Tuhia anō te a^{2}+a-2 hei \left(a^{2}-a\right)+\left(2a-2\right).

a\left(a-1\right)+2\left(a-1\right)

Tauwehea te a i te tuatahi me te 2 i te rōpū tuarua.

\left(a-1\right)\left(a+2\right)

Whakatauwehea atu te kīanga pātahi a-1 mā te whakamahi i te āhuatanga tātai tohatoha.

\left(2a-3\right)\left(a-1\right)\left(a+2\right)

Me tuhi anō te kīanga whakatauwehe katoa.