Whakaoti i te f(x)=x/x+5

$$f ( x ) = \frac { x } { x + 5 }$$

Kimi Pārōnaki e ai ki x

$$\frac{5}{\left(x+5\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}+5\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1})-x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+5)}{\left(x^{1}+5\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}+5\right)x^{1-1}-x^{1}x^{1-1}}{\left(x^{1}+5\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}+5\right)x^{0}-x^{1}x^{0}}{\left(x^{1}+5\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}x^{0}+5x^{0}-x^{1}x^{0}}{\left(x^{1}+5\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{x^{1}+5x^{0}-x^{1}}{\left(x^{1}+5\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(1-1\right)x^{1}+5x^{0}}{\left(x^{1}+5\right)^{2}}$$

Tango 1 mai i 1.

$$\frac{5x^{0}}{\left(x^{1}+5\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{5x^{0}}{\left(x+5\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{5\times 1}{\left(x+5\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{5}{\left(x+5\right)^{2}}$$

Aromātai

$$\frac{x}{x+5}$$