Whakaoti i te f(x)=x^2/x^2-4

$$f ( x ) = \frac { x ^ { 2 } } { x ^ { 2 } - 4 }$$

Kimi Pārōnaki e ai ki x

$$-\frac{8x}{\left(x^{2}-4\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{2}-4\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{2})-x^{2}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}-4)}{\left(x^{2}-4\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{2}-4\right)\times 2x^{2-1}-x^{2}\times 2x^{2-1}}{\left(x^{2}-4\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{2}-4\right)\times 2x^{1}-x^{2}\times 2x^{1}}{\left(x^{2}-4\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{2}\times 2x^{1}-4\times 2x^{1}-x^{2}\times 2x^{1}}{\left(x^{2}-4\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2x^{2+1}-4\times 2x^{1}-2x^{2+1}}{\left(x^{2}-4\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{2x^{3}-8x^{1}-2x^{3}}{\left(x^{2}-4\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(2-2\right)x^{3}-8x^{1}}{\left(x^{2}-4\right)^{2}}$$

Tango 2 mai i 2.

$$\frac{-8x^{1}}{\left(x^{2}-4\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-8x}{\left(x^{2}-4\right)^{2}}$$

Aromātai

$$\frac{x^{2}}{x^{2}-4}$$