Whakaoti i te f(x)=5x/9-x

$$f ( x ) = \frac { 5 x } { 9 - x }$$

Kimi Pārōnaki e ai ki x

$$\frac{45}{\left(x-9\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(-x^{1}+9\right)\frac{\mathrm{d}}{\mathrm{d}x}(5x^{1})-5x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(-x^{1}+9)}{\left(-x^{1}+9\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(-x^{1}+9\right)\times 5x^{1-1}-5x^{1}\left(-1\right)x^{1-1}}{\left(-x^{1}+9\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(-x^{1}+9\right)\times 5x^{0}-5x^{1}\left(-1\right)x^{0}}{\left(-x^{1}+9\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{-x^{1}\times 5x^{0}+9\times 5x^{0}-5x^{1}\left(-1\right)x^{0}}{\left(-x^{1}+9\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{-5x^{1}+9\times 5x^{0}-5\left(-1\right)x^{1}}{\left(-x^{1}+9\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{-5x^{1}+45x^{0}-\left(-5x^{1}\right)}{\left(-x^{1}+9\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(-5-\left(-5\right)\right)x^{1}+45x^{0}}{\left(-x^{1}+9\right)^{2}}$$

Tango -5 mai i -5.

$$\frac{45x^{0}}{\left(-x^{1}+9\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{45x^{0}}{\left(-x+9\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{45\times 1}{\left(-x+9\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{45}{\left(-x+9\right)^{2}}$$

Aromātai

$$\frac{5x}{9-x}$$