Whakaoti i te f(x)=3x/1+x^3

$$f ( x ) = \frac { 3 x } { 1 + x ^ { 3 } }$$

Kimi Pārōnaki e ai ki x

$$\frac{3\left(1-2x^{3}\right)}{\left(x^{3}+1\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{3}+1\right)\frac{\mathrm{d}}{\mathrm{d}x}(3x^{1})-3x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}+1)}{\left(x^{3}+1\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{3}+1\right)\times 3x^{1-1}-3x^{1}\times 3x^{3-1}}{\left(x^{3}+1\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{3}+1\right)\times 3x^{0}-3x^{1}\times 3x^{2}}{\left(x^{3}+1\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{3}\times 3x^{0}+3x^{0}-3x^{1}\times 3x^{2}}{\left(x^{3}+1\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{3x^{3}+3x^{0}-3\times 3x^{1+2}}{\left(x^{3}+1\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{3x^{3}+3x^{0}-9x^{3}}{\left(x^{3}+1\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(3-9\right)x^{3}+3x^{0}}{\left(x^{3}+1\right)^{2}}$$

Tango 9 mai i 3.

$$\frac{-6x^{3}+3x^{0}}{\left(x^{3}+1\right)^{2}}$$

Tauwehea te 3.

$$\frac{3\left(-2x^{3}+x^{0}\right)}{\left(x^{3}+1\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{3\left(-2x^{3}+1\right)}{\left(x^{3}+1\right)^{2}}$$

Aromātai

$$\frac{3x}{x^{3}+1}$$