Whakaoti i te f(x)=3/x+2+1

$$f ( x ) = \frac { 3 } { x + 2 } + 1$$

Aromātai

$$\frac{x+5}{x+2}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{x+2}{x+2}.

$$\frac{3}{x+2}+\frac{x+2}{x+2}$$

Tā te mea he rite te tauraro o \frac{3}{x+2} me \frac{x+2}{x+2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3+x+2}{x+2}$$

Whakakotahitia ngā kupu rite i 3+x+2.

$$\frac{5+x}{x+2}$$

Kimi Pārōnaki e ai ki x

$$-\frac{3}{\left(x+2\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{x+2}{x+2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3}{x+2}+\frac{x+2}{x+2})$$

Tā te mea he rite te tauraro o \frac{3}{x+2} me \frac{x+2}{x+2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3+x+2}{x+2})$$

Whakakotahitia ngā kupu rite i 3+x+2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5+x}{x+2})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}+2\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+5)-\left(x^{1}+5\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+2)}{\left(x^{1}+2\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}+2\right)x^{1-1}-\left(x^{1}+5\right)x^{1-1}}{\left(x^{1}+2\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}+2\right)x^{0}-\left(x^{1}+5\right)x^{0}}{\left(x^{1}+2\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}x^{0}+2x^{0}-\left(x^{1}x^{0}+5x^{0}\right)}{\left(x^{1}+2\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{x^{1}+2x^{0}-\left(x^{1}+5x^{0}\right)}{\left(x^{1}+2\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{x^{1}+2x^{0}-x^{1}-5x^{0}}{\left(x^{1}+2\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(1-1\right)x^{1}+\left(2-5\right)x^{0}}{\left(x^{1}+2\right)^{2}}$$

Tangohia te 1 i 1 me te 5 i te 2.

$$\frac{-3x^{0}}{\left(x^{1}+2\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-3x^{0}}{\left(x+2\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-3}{\left(x+2\right)^{2}}$$