Whakaoti i te f(x)=2/x+3-5

$$f ( x ) = \frac { 2 } { x + 3 } - 5$$

Aromātai

$$-\frac{5x+13}{x+3}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 5 ki te \frac{x+3}{x+3}.

$$\frac{2}{x+3}-\frac{5\left(x+3\right)}{x+3}$$

Tā te mea he rite te tauraro o \frac{2}{x+3} me \frac{5\left(x+3\right)}{x+3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{2-5\left(x+3\right)}{x+3}$$

Mahia ngā whakarea i roto o 2-5\left(x+3\right).

$$\frac{2-5x-15}{x+3}$$

Whakakotahitia ngā kupu rite i 2-5x-15.

$$\frac{-13-5x}{x+3}$$

Kimi Pārōnaki e ai ki x

$$-\frac{2}{\left(x+3\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 5 ki te \frac{x+3}{x+3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2}{x+3}-\frac{5\left(x+3\right)}{x+3})$$

Tā te mea he rite te tauraro o \frac{2}{x+3} me \frac{5\left(x+3\right)}{x+3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2-5\left(x+3\right)}{x+3})$$

Mahia ngā whakarea i roto o 2-5\left(x+3\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2-5x-15}{x+3})$$

Whakakotahitia ngā kupu rite i 2-5x-15.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{-13-5x}{x+3})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}+3\right)\frac{\mathrm{d}}{\mathrm{d}x}(-5x^{1}-13)-\left(-5x^{1}-13\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+3)}{\left(x^{1}+3\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}+3\right)\left(-5\right)x^{1-1}-\left(-5x^{1}-13\right)x^{1-1}}{\left(x^{1}+3\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}+3\right)\left(-5\right)x^{0}-\left(-5x^{1}-13\right)x^{0}}{\left(x^{1}+3\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\left(-5\right)x^{0}+3\left(-5\right)x^{0}-\left(-5x^{1}x^{0}-13x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{-5x^{1}+3\left(-5\right)x^{0}-\left(-5x^{1}-13x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{-5x^{1}-15x^{0}-\left(-5x^{1}-13x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{-5x^{1}-15x^{0}-\left(-5x^{1}\right)-\left(-13x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(-5-\left(-5\right)\right)x^{1}+\left(-15-\left(-13\right)\right)x^{0}}{\left(x^{1}+3\right)^{2}}$$

Tangohia te -5 i -5 me te -13 i te -15.

$$\frac{-2x^{0}}{\left(x^{1}+3\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-2x^{0}}{\left(x+3\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-2}{\left(x+3\right)^{2}}$$