Whakaoti i te f(x)=1/1-x^2*g(x)=x^2

$$f ( x ) = \frac { 1 } { 1 - x ^ { 2 } } \cdot g ( x ) = x ^ { 2 }$$

Whakaoti mō g

$$\left\{\begin{matrix}g=x-x^{3}\text{, }&|x|\neq 1\\g\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te \left(x-1\right)\left(-x-1\right).

$$1gx=\left(x-1\right)\left(-x-1\right)x^{2}$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x-1 ki te -x-1 ka whakakotahi i ngā kupu rite.

$$1gx=\left(-x^{2}+1\right)x^{2}$$

Whakamahia te āhuatanga tohatoha hei whakarea te -x^{2}+1 ki te x^{2}.

$$1gx=-x^{4}+x^{2}$$

Whakaraupapatia anō ngā kīanga tau.

$$gx=-x^{4}+x^{2}$$

He hanga arowhānui tō te whārite.

$$xg=x^{2}-x^{4}$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xg}{x}=\frac{x^{2}-x^{4}}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$g=\frac{x^{2}-x^{4}}{x}$$

Whakawehe -x^{4}+x^{2} ki te x.

$$g=x-x^{3}$$