Whakaoti i te f(x)=cot2x

$$f ( x ) = \cot 2 x$$

Kimi Pārōnaki e ai ki x

$$-\frac{2}{\left(\sin(2x)\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$\left(-\left(\csc(2x^{1})\right)^{2}\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\left(-\left(\csc(2x^{1})\right)^{2}\right)\times 2x^{1-1}$$

Whakarūnātia.

$$-2\left(\csc(2x^{1})\right)^{2}$$

Mō tētahi kupu t, t^{1}=t.

$$-2\left(\csc(2x)\right)^{2}$$

Aromātai

$$\cot(2x)$$