Whakaoti i te f(c)=23/4+(-11/2)-(-12/3)

$$f ( c ) = 2 \frac { 3 } { 4 } + ( - 1 \frac { 1 } { 2 } ) - ( - 1 \frac { 2 } { 3 } )$$

Aromātai

$$\frac{35}{12}\approx 2.916666667$$

Ngā Upane Otinga

Whakareatia te 2 ki te 4, ka 8.

$$\frac{8+3}{4}-\frac{1\times 2+1}{2}-\left(-\frac{1\times 3+2}{3}\right)$$

Tāpirihia te 8 ki te 3, ka 11.

$$\frac{11}{4}-\frac{1\times 2+1}{2}-\left(-\frac{1\times 3+2}{3}\right)$$

Whakareatia te 1 ki te 2, ka 2.

$$\frac{11}{4}-\frac{2+1}{2}-\left(-\frac{1\times 3+2}{3}\right)$$

Tāpirihia te 2 ki te 1, ka 3.

$$\frac{11}{4}-\frac{3}{2}-\left(-\frac{1\times 3+2}{3}\right)$$

Ko te maha noa iti rawa atu o 4 me 2 ko 4. Me tahuri \frac{11}{4} me \frac{3}{2} ki te hautau me te tautūnga 4.

$$\frac{11}{4}-\frac{6}{4}-\left(-\frac{1\times 3+2}{3}\right)$$

Tā te mea he rite te tauraro o \frac{11}{4} me \frac{6}{4}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{11-6}{4}-\left(-\frac{1\times 3+2}{3}\right)$$

Tangohia te 6 i te 11, ka 5.

$$\frac{5}{4}-\left(-\frac{1\times 3+2}{3}\right)$$

Whakareatia te 1 ki te 3, ka 3.

$$\frac{5}{4}-\left(-\frac{3+2}{3}\right)$$

Tāpirihia te 3 ki te 2, ka 5.

$$\frac{5}{4}-\left(-\frac{5}{3}\right)$$

Ko te tauaro o -\frac{5}{3} ko \frac{5}{3}.

$$\frac{5}{4}+\frac{5}{3}$$

Ko te maha noa iti rawa atu o 4 me 3 ko 12. Me tahuri \frac{5}{4} me \frac{5}{3} ki te hautau me te tautūnga 12.

$$\frac{15}{12}+\frac{20}{12}$$

Tā te mea he rite te tauraro o \frac{15}{12} me \frac{20}{12}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{15+20}{12}$$

Tāpirihia te 15 ki te 20, ka 35.

$$\frac{35}{12}$$

Tauwehe

$$\frac{5 \cdot 7}{2 ^ {2} \cdot 3} = 2\frac{11}{12} = 2.9166666666666665$$