Whakaoti i te f(1)=14x^2/x^4+49

$$f ( 1 ) = \frac { 14 x ^ { 2 } } { x ^ { 4 } + 49 }$$

Kimi Pārōnaki e ai ki x

$$\frac{28x\left(49-x^{4}\right)}{\left(x^{4}+49\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{4}+49\right)\frac{\mathrm{d}}{\mathrm{d}x}(14x^{2})-14x^{2}\frac{\mathrm{d}}{\mathrm{d}x}(x^{4}+49)}{\left(x^{4}+49\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{4}+49\right)\times 2\times 14x^{2-1}-14x^{2}\times 4x^{4-1}}{\left(x^{4}+49\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{4}+49\right)\times 28x^{1}-14x^{2}\times 4x^{3}}{\left(x^{4}+49\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{4}\times 28x^{1}+49\times 28x^{1}-14x^{2}\times 4x^{3}}{\left(x^{4}+49\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{28x^{4+1}+49\times 28x^{1}-14\times 4x^{2+3}}{\left(x^{4}+49\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{28x^{5}+1372x^{1}-56x^{5}}{\left(x^{4}+49\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(28-56\right)x^{5}+1372x^{1}}{\left(x^{4}+49\right)^{2}}$$

Tango 56 mai i 28.

$$\frac{-28x^{5}+1372x^{1}}{\left(x^{4}+49\right)^{2}}$$

Tauwehea te 28x.

$$\frac{28x\left(-x^{4}+49x^{0}\right)}{\left(x^{4}+49\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{28x\left(-x^{4}+49\times 1\right)}{\left(x^{4}+49\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{28x\left(-x^{4}+49\right)}{\left(x^{4}+49\right)^{2}}$$

Aromātai

$$\frac{14x^{2}}{x^{4}+49}$$