Whakaoti i te f(-1/3)=(-1/3)-1/2(-frac{1{3})^2-(-1/3)^2}=

$$f ( - \frac { 1 } { 3 } ) = \frac { ( - \frac { 1 } { 3 } ) - 1 } { 2 ( - \frac { 1 } { 3 } ) ^ { 2 } - ( - \frac { 1 } { 3 } ) ^ { 2 } } =$$

Aromātai

$$-12$$

Ngā Upane Otinga

Me tahuri te 1 ki te hautau \frac{3}{3}.

$$\frac{-\frac{1}{3}-\frac{3}{3}}{2\left(-\frac{1}{3}\right)^{2}-\left(-\frac{1}{3}\right)^{2}}$$

Tā te mea he rite te tauraro o -\frac{1}{3} me \frac{3}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\frac{-1-3}{3}}{2\left(-\frac{1}{3}\right)^{2}-\left(-\frac{1}{3}\right)^{2}}$$

Tangohia te 3 i te -1, ka -4.

$$\frac{-\frac{4}{3}}{2\left(-\frac{1}{3}\right)^{2}-\left(-\frac{1}{3}\right)^{2}}$$

Tātaihia te -\frac{1}{3} mā te pū o 2, kia riro ko \frac{1}{9}.

$$\frac{-\frac{4}{3}}{2\times \frac{1}{9}-\left(-\frac{1}{3}\right)^{2}}$$

Whakareatia te 2 ki te \frac{1}{9}, ka \frac{2}{9}.

$$\frac{-\frac{4}{3}}{\frac{2}{9}-\left(-\frac{1}{3}\right)^{2}}$$

Tātaihia te -\frac{1}{3} mā te pū o 2, kia riro ko \frac{1}{9}.

$$\frac{-\frac{4}{3}}{\frac{2}{9}-\frac{1}{9}}$$

Tā te mea he rite te tauraro o \frac{2}{9} me \frac{1}{9}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-\frac{4}{3}}{\frac{2-1}{9}}$$

Tangohia te 1 i te 2, ka 1.

$$\frac{-\frac{4}{3}}{\frac{1}{9}}$$

Whakawehe -\frac{4}{3} ki te \frac{1}{9} mā te whakarea -\frac{4}{3} ki te tau huripoki o \frac{1}{9}.

$$-\frac{4}{3}\times 9$$

Tuhia te -\frac{4}{3}\times 9 hei hautanga kotahi.

$$\frac{-4\times 9}{3}$$

Whakareatia te -4 ki te 9, ka -36.

$$\frac{-36}{3}$$

Whakawehea te -36 ki te 3, kia riro ko -12.

$$-12$$

Tauwehe

$$-12$$