Whakaoti i te f(-1/2)f(3)+(0)

$$f ( - \frac { 1 } { 2 } ) f ( 3 ) + ( 0 )$$

Aromātai

$$-\frac{3f^{2}}{2}$$

Ngā Upane Otinga

Whakareatia te f ki te f, ka f^{2}.

$$f^{2}\left(-\frac{1}{2}\right)\times 3+0$$

Tuhia te -\frac{1}{2}\times 3 hei hautanga kotahi.

$$f^{2}\times \frac{-3}{2}+0$$

Ka taea te hautanga \frac{-3}{2} te tuhi anō ko -\frac{3}{2} mā te tango i te tohu tōraro.

$$f^{2}\left(-\frac{3}{2}\right)+0$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$f^{2}\left(-\frac{3}{2}\right)$$

Kimi Pārōnaki e ai ki f

$$-3f$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Whakareatia te f ki te f, ka f^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}f}(f^{2}\left(-\frac{1}{2}\right)\times 3+0)$$

Tuhia te -\frac{1}{2}\times 3 hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}f}(f^{2}\times \frac{-3}{2}+0)$$

Ka taea te hautanga \frac{-3}{2} te tuhi anō ko -\frac{3}{2} mā te tango i te tohu tōraro.

$$\frac{\mathrm{d}}{\mathrm{d}f}(f^{2}\left(-\frac{3}{2}\right)+0)$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$\frac{\mathrm{d}}{\mathrm{d}f}(f^{2}\left(-\frac{3}{2}\right))$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$2\left(-\frac{3}{2}\right)f^{2-1}$$

Whakareatia 2 ki te -\frac{3}{2}.

$$-3f^{2-1}$$

Tango 1 mai i 2.

$$-3f^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$-3f$$