Whakaoti i te f(3-y/4)=3-4(3-y/4)

$$f ( \frac { 3 - y } { 4 } ) = 3 - 4 ( \frac { 3 - y } { 4 } )$$

Aromātai

$$y$$

Ngā Upane Otinga

Me whakakore te 4 me te 4.

$$3-\left(3-y\right)$$

Hei kimi i te tauaro o 3-y, kimihia te tauaro o ia taurangi.

$$3-3-\left(-y\right)$$

Ko te tauaro o -y ko y.

$$3-3+y$$

Tangohia te 3 i te 3, ka 0.

$$y$$

Kimi Pārōnaki e ai ki y

$$1$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Me whakakore te 4 me te 4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(3-\left(3-y\right))$$

Hei kimi i te tauaro o 3-y, kimihia te tauaro o ia taurangi.

$$\frac{\mathrm{d}}{\mathrm{d}y}(3-3-\left(-y\right))$$

Ko te tauaro o -y ko y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(3-3+y)$$

Tangohia te 3 i te 3, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$y^{1-1}$$

Tango 1 mai i 1.

$$y^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$1$$