Whakaoti i te f^2=1

$$f ^ { 2 } = 1$$

Whakaoti mō f

$$f=1$$

$$f=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$f^{2}-1=0$$

Whakaarohia te f^{2}-1. Tuhia anō te f^{2}-1 hei f^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(f-1\right)\left(f+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te f-1=0 me te f+1=0.

$$f=1 f=-1$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$f=1 f=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$f^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$f=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$f=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$f=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$f=\frac{0±2}{2}$$

Nā, me whakaoti te whārite f=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$f=1$$

Nā, me whakaoti te whārite f=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$f=-1$$

Kua oti te whārite te whakatau.

$$f=1 f=-1$$