Whakaoti i te f^2+8f+7

$$f ^ { 2 } + 8 f + 7$$

Tauwehe

$$\left(f+1\right)\left(f+7\right)$$

Ngā Upane Otinga

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei f^{2}+af+bf+7. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=8 ab=1\times 7=7$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=1 b=7$$

Tuhia anō te f^{2}+8f+7 hei \left(f^{2}+f\right)+\left(7f+7\right).

$$\left(f^{2}+f\right)+\left(7f+7\right)$$

Tauwehea te f i te tuatahi me te 7 i te rōpū tuarua.

$$f\left(f+1\right)+7\left(f+1\right)$$

Whakatauwehea atu te kīanga pātahi f+1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(f+1\right)\left(f+7\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$f^{2}+8f+7=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$f=\frac{-8±\sqrt{8^{2}-4\times 7}}{2}$$

Pūrua 8.

$$f=\frac{-8±\sqrt{64-4\times 7}}{2}$$

Whakareatia -4 ki te 7.

$$f=\frac{-8±\sqrt{64-28}}{2}$$

Tāpiri 64 ki te -28.

$$f=\frac{-8±\sqrt{36}}{2}$$

Tuhia te pūtakerua o te 36.

$$f=\frac{-8±6}{2}$$

Nā, me whakaoti te whārite f=\frac{-8±6}{2} ina he tāpiri te ±. Tāpiri -8 ki te 6.

$$f=-\frac{2}{2}$$

Whakawehe -2 ki te 2.

$$f=-1$$

Nā, me whakaoti te whārite f=\frac{-8±6}{2} ina he tango te ±. Tango 6 mai i -8.

$$f=-\frac{14}{2}$$

Whakawehe -14 ki te 2.

$$f=-7$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -1 mō te x_{1} me te -7 mō te x_{2}.

$$f^{2}+8f+7=\left(f-\left(-1\right)\right)\left(f-\left(-7\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$f^{2}+8f+7=\left(f+1\right)\left(f+7\right)$$

Aromātai

$$\left(f+1\right)\left(f+7\right)$$