Whakaoti i te f^-1(x)=sqrt[3]{3+x}

$$f ^ { - 1 } ( x ) = \sqrt[ 3 ] { 3 + x }$$

Whakaoti mō f

$$f=\frac{x}{\sqrt[3]{x+3}}$$

$$x\neq 0\text{ and }x\neq -3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakaraupapatia anō ngā kīanga tau.

$$\frac{1}{f}x=\sqrt[3]{x+3}$$

Tē taea kia ōrite te tāupe f ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te f.

$$1x=f\sqrt[3]{x+3}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$f\sqrt[3]{x+3}=1x$$

Whakaraupapatia anō ngā kīanga tau.

$$\sqrt[3]{x+3}f=x$$

Whakawehea ngā taha e rua ki te \sqrt[3]{3+x}.

$$\frac{\sqrt[3]{x+3}f}{\sqrt[3]{x+3}}=\frac{x}{\sqrt[3]{x+3}}$$

Mā te whakawehe ki te \sqrt[3]{3+x} ka wetekia te whakareanga ki te \sqrt[3]{3+x}.

$$f=\frac{x}{\sqrt[3]{x+3}}$$

Tē taea kia ōrite te tāupe f ki 0.

$$f=\frac{x}{\sqrt[3]{x+3}}\text{, }f\neq 0$$