Whakaoti i te f^-1(x)=-x+8/5

$$f ^ { - 1 } ( x ) = \frac { - x + 8 } { 5 }$$

Whakaoti mō f

$$f=-\frac{5x}{x-8}$$

$$x\neq 0\text{ and }x\neq 8$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 5.

$$5f^{-1}x=-x+8$$

Whakaraupapatia anō ngā kīanga tau.

$$5\times \frac{1}{f}x=8-x$$

Tē taea kia ōrite te tāupe f ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te f.

$$5\times 1x=f\times 8-xf$$

Whakareatia te 5 ki te 1, ka 5.

$$5x=f\times 8-xf$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$f\times 8-xf=5x$$

Pahekotia ngā kīanga tau katoa e whai ana i te f.

$$\left(8-x\right)f=5x$$

Whakawehea ngā taha e rua ki te 8-x.

$$\frac{\left(8-x\right)f}{8-x}=\frac{5x}{8-x}$$

Mā te whakawehe ki te 8-x ka wetekia te whakareanga ki te 8-x.

$$f=\frac{5x}{8-x}$$

Tē taea kia ōrite te tāupe f ki 0.

$$f=\frac{5x}{8-x}\text{, }f\neq 0$$

Whakaoti mō x

$$x=\frac{8f}{f+5}$$

$$f\neq -5\text{ and }f\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 5.

$$5f^{-1}x=-x+8$$

Me tāpiri te x ki ngā taha e rua.

$$5f^{-1}x+x=8$$

Whakaraupapatia anō ngā kīanga tau.

$$x+5\times \frac{1}{f}x=8$$

Whakareatia ngā taha e rua o te whārite ki te f.

$$fx+5\times 1x=8f$$

Whakareatia te 5 ki te 1, ka 5.

$$fx+5x=8f$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(f+5\right)x=8f$$

Whakawehea ngā taha e rua ki te 5+f.

$$\frac{\left(f+5\right)x}{f+5}=\frac{8f}{f+5}$$

Mā te whakawehe ki te 5+f ka wetekia te whakareanga ki te 5+f.

$$x=\frac{8f}{f+5}$$