Whakaoti i te ex^3-23x^2+142x-120

$$e x ^ { 3 } - 23 x ^ { 2 } + 142 x - 120$$

Kimi Pārōnaki e ai ki x

$$3ex^{2}-46x+142$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3ex^{3-1}+2\left(-23\right)x^{2-1}+142x^{1-1}$$

Tango 1 mai i 3.

$$3ex^{2}+2\left(-23\right)x^{2-1}+142x^{1-1}$$

Whakareatia 2 ki te -23.

$$3ex^{2}-46x^{2-1}+142x^{1-1}$$

Tango 1 mai i 2.

$$3ex^{2}-46x^{1}+142x^{1-1}$$

Tango 1 mai i 1.

$$3ex^{2}-46x^{1}+142x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$3ex^{2}-46x+142x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$3ex^{2}-46x+142\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$3ex^{2}-46x+142$$

Aromātai

$$ex^{3}-23x^{2}+142x-120$$