Whakaoti i te e^bb+b*x=b-10

$$e ^ { b b } + b \times x = b - 10$$

Whakaoti mō x

$$x=-\frac{10+e^{b^{2}}-b}{b}$$

$$b\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te b ki te b, ka b^{2}.

$$e^{b^{2}}+bx=b-10$$

Tangohia te e^{b^{2}} mai i ngā taha e rua.

$$bx=b-10-e^{b^{2}}$$

Whakaraupapatia anō ngā kīanga tau.

$$bx=-e^{b^{2}}+b-10$$

He hanga arowhānui tō te whārite.

$$bx=b-e^{b^{2}}-10$$

Whakawehea ngā taha e rua ki te b.

$$\frac{bx}{b}=\frac{b-e^{b^{2}}-10}{b}$$

Mā te whakawehe ki te b ka wetekia te whakareanga ki te b.

$$x=\frac{b-e^{b^{2}}-10}{b}$$