Whakaoti i te dh(t)=2t^2-4r

$$d h ( t ) = 2 t ^ { 2 } - 4 r$$

Whakaoti mō r

$$r=\frac{t^{2}}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2t^{2}-4r=\frac{\mathrm{d}}{\mathrm{d}h}(t)$$

Tangohia te 2t^{2} mai i ngā taha e rua.

$$-4r=\frac{\mathrm{d}}{\mathrm{d}h}(t)-2t^{2}$$

He hanga arowhānui tō te whārite.

$$-4r=-2t^{2}$$

Whakawehea ngā taha e rua ki te -4.

$$\frac{-4r}{-4}=-\frac{2t^{2}}{-4}$$

Mā te whakawehe ki te -4 ka wetekia te whakareanga ki te -4.

$$r=-\frac{2t^{2}}{-4}$$

Whakawehe -2t^{2} ki te -4.

$$r=\frac{t^{2}}{2}$$

Whakaoti mō h

$$h\in \mathrm{R}$$

$$r=\frac{t^{2}}{2}$$