Whakaoti i te d(pi/2-x)=-dx

$$d ( \frac { \pi } { 2 } - x ) = - d x$$

Whakaoti mō d

$$d=0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2d\left(\frac{\pi }{2}-x\right)=2\left(-d\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2d ki te \frac{\pi }{2}-x.

$$2d\times \frac{\pi }{2}-2dx=2\left(-d\right)x$$

Tuhia te 2\times \frac{\pi }{2} hei hautanga kotahi.

$$\frac{2\pi }{2}d-2dx=2\left(-d\right)x$$

Me whakakore te 2 me te 2.

$$\pi d-2dx=2\left(-d\right)x$$

Tangohia te 2\left(-d\right)x mai i ngā taha e rua.

$$\pi d-2dx-2\left(-d\right)x=0$$

Whakareatia te -1 ki te 2, ka -2.

$$\pi d-2dx-2\left(-1\right)dx=0$$

Whakareatia te -2 ki te -1, ka 2.

$$\pi d-2dx+2dx=0$$

Pahekotia te -2dx me 2dx, ka 0.

$$\pi d=0$$

Whakawehe 0 ki te \pi .

$$d=0$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}$$

$$d=0$$

Whakaoti mō x

$$x\in \mathrm{R}$$

$$d=0$$