Whakaoti i te d=(2)^2+(-3)+(m-3)^2

$$d = ( 2 ) ^ { 2 } + ( - 3 ) + ( m - 3 ) ^ { 2 }$$

Whakaoti mō d

$$d=\left(m-3\right)^{2}+1$$

Ngā Upane Otinga

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$d=4-3+\left(m-3\right)^{2}$$

Tangohia te 3 i te 4, ka 1.

$$d=1+\left(m-3\right)^{2}$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(m-3\right)^{2}.

$$d=1+m^{2}-6m+9$$

Tāpirihia te 1 ki te 9, ka 10.

$$d=10+m^{2}-6m$$

Whakaoti mō m (complex solution)

$$m=-\sqrt{d-1}+3$$

$$m=\sqrt{d-1}+3$$

Whakaoti mō m

$$m=-\sqrt{d-1}+3$$

$$m=\sqrt{d-1}+3\text{, }d\geq 1$$