Whakaoti i te c=(x+1)(2+x)-(x+1)(4x-8)

$$c = ( x + 1 ) ( 2 + x ) - ( x + 1 ) ( 4 x - 8 )$$

Whakaoti mō c

$$c=\left(10-3x\right)\left(x+1\right)$$

Ngā Upane Otinga

Whakamahia te āhuatanga tuaritanga hei whakarea te x+1 ki te 2+x ka whakakotahi i ngā kupu rite.

$$c=3x+x^{2}+2-\left(x+1\right)\left(4x-8\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x+1 ki te 4x-8 ka whakakotahi i ngā kupu rite.

$$c=3x+x^{2}+2-\left(4x^{2}-4x-8\right)$$

Hei kimi i te tauaro o 4x^{2}-4x-8, kimihia te tauaro o ia taurangi.

$$c=3x+x^{2}+2-4x^{2}+4x+8$$

Pahekotia te x^{2} me -4x^{2}, ka -3x^{2}.

$$c=3x-3x^{2}+2+4x+8$$

Pahekotia te 3x me 4x, ka 7x.

$$c=7x-3x^{2}+2+8$$

Tāpirihia te 2 ki te 8, ka 10.

$$c=7x-3x^{2}+10$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{169-12c}+7}{6}$$

$$x=\frac{-\sqrt{169-12c}+7}{6}$$

Whakaoti mō x

$$x=\frac{\sqrt{169-12c}+7}{6}$$

$$x=\frac{-\sqrt{169-12c}+7}{6}\text{, }c\leq \frac{169}{12}$$