Whakaoti i te c=4-d/d+3

$$c = \frac { 4 - d } { d + 3 }$$

Whakaoti mō d

$$d=-\frac{3c-4}{c+1}$$

$$c\neq -1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe d ki -3 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te d+3.

$$c\left(d+3\right)=4-d$$

Whakamahia te āhuatanga tohatoha hei whakarea te c ki te d+3.

$$cd+3c=4-d$$

Me tāpiri te d ki ngā taha e rua.

$$cd+3c+d=4$$

Tangohia te 3c mai i ngā taha e rua.

$$cd+d=4-3c$$

Pahekotia ngā kīanga tau katoa e whai ana i te d.

$$\left(c+1\right)d=4-3c$$

Whakawehea ngā taha e rua ki te c+1.

$$\frac{\left(c+1\right)d}{c+1}=\frac{4-3c}{c+1}$$

Mā te whakawehe ki te c+1 ka wetekia te whakareanga ki te c+1.

$$d=\frac{4-3c}{c+1}$$

Tē taea kia ōrite te tāupe d ki -3.

$$d=\frac{4-3c}{c+1}\text{, }d\neq -3$$

Whakaoti mō c

$$c=-\frac{d-4}{d+3}$$

$$d\neq -3$$