Whakaoti i te c=1+tan(2pi/9)^2/sqrt{(4^2+1)}

$$c = \frac { 1 + \tan ( 2 \frac { \pi } { 9 } ) ^ { 2 } } { \sqrt { ( 4 ^ { 2 } + 1 ) } }$$

Whakaoti mō c

$$c=\frac{170408819104184715837886196294401\sqrt{17}}{1700000000000000000000000000000000}\approx 0.413302095$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Evaluate trigonometric functions in the problem

$$c = \frac{1 + 0.8390996311772799 ^ {2}}{\sqrt{{(4 ^ {2} + 1)}}}$$

Tātaihia te 0.8390996311772799 mā te pū o 2, kia riro ko 0.70408819104184715837886196294401.

$$c=\frac{1+0.70408819104184715837886196294401}{\sqrt{4^{2}+1}}$$

Tāpirihia te 1 ki te 0.70408819104184715837886196294401, ka 1.70408819104184715837886196294401.

$$c=\frac{1.70408819104184715837886196294401}{\sqrt{4^{2}+1}}$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$c=\frac{1.70408819104184715837886196294401}{\sqrt{16+1}}$$

Tāpirihia te 16 ki te 1, ka 17.

$$c=\frac{1.70408819104184715837886196294401}{\sqrt{17}}$$

Whakangāwaritia te tauraro o \frac{1.70408819104184715837886196294401}{\sqrt{17}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{17}.

$$c=\frac{1.70408819104184715837886196294401\sqrt{17}}{\left(\sqrt{17}\right)^{2}}$$

Ko te pūrua o \sqrt{17} ko 17.

$$c=\frac{1.70408819104184715837886196294401\sqrt{17}}{17}$$

Whakawehea te 1.70408819104184715837886196294401\sqrt{17} ki te 17, kia riro ko \frac{170408819104184715837886196294401}{1700000000000000000000000000000000}\sqrt{17}.

$$c=\frac{170408819104184715837886196294401}{1700000000000000000000000000000000}\sqrt{17}$$

Tautapa c

$$c≔\frac{170408819104184715837886196294401\sqrt{17}}{1700000000000000000000000000000000}$$