Whakaoti mō a
a=\frac{n}{2}+\frac{1}{2b}
b\neq 0
Whakaoti mō b
b=-\frac{1}{n-2a}
n\neq 2a
Tohaina
Kua tāruatia ki te papatopenga
2ba=bn+1
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
\frac{2ba}{2b}=\frac{bn+1}{2b}
Whakawehea ngā taha e rua ki te 2b.
a=\frac{bn+1}{2b}
Mā te whakawehe ki te 2b ka wetekia te whakareanga ki te 2b.
a=\frac{n}{2}+\frac{1}{2b}
Whakawehe bn+1 ki te 2b.
bn+1-2ba=0
Tangohia te 2ba mai i ngā taha e rua.
bn-2ba=-1
Tangohia te 1 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.
\left(n-2a\right)b=-1
Pahekotia ngā kīanga tau katoa e whai ana i te b.
\frac{\left(n-2a\right)b}{n-2a}=-\frac{1}{n-2a}
Whakawehea ngā taha e rua ki te n-2a.
b=-\frac{1}{n-2a}
Mā te whakawehe ki te n-2a ka wetekia te whakareanga ki te n-2a.
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