Whakaoti i te b_{0}x=1/2[100*(22-x)]

$$b _ { 0 } x = \frac { 1 } { 2 } [ 100 \times ( 22 - x ) ]$$

Whakaoti mō b_0

$$b_{0}=-50+\frac{1100}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te \frac{1}{2} ki te 100, ka 50.

$$b_{0}x=50\left(22-x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 50 ki te 22-x.

$$b_{0}x=1100-50x$$

He hanga arowhānui tō te whārite.

$$xb_{0}=1100-50x$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xb_{0}}{x}=\frac{1100-50x}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$b_{0}=\frac{1100-50x}{x}$$

Whakawehe 1100-50x ki te x.

$$b_{0}=-50+\frac{1100}{x}$$

Whakaoti mō x

$$x=\frac{1100}{b_{0}+50}$$

$$b_{0}\neq -50$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te \frac{1}{2} ki te 100, ka 50.

$$b_{0}x=50\left(22-x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 50 ki te 22-x.

$$b_{0}x=1100-50x$$

Me tāpiri te 50x ki ngā taha e rua.

$$b_{0}x+50x=1100$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(b_{0}+50\right)x=1100$$

Whakawehea ngā taha e rua ki te b_{0}+50.

$$\frac{\left(b_{0}+50\right)x}{b_{0}+50}=\frac{1100}{b_{0}+50}$$

Mā te whakawehe ki te b_{0}+50 ka wetekia te whakareanga ki te b_{0}+50.

$$x=\frac{1100}{b_{0}+50}$$