Whakaoti i te b^2-6b+9

$$b ^ { 2 } - 6 b + 9$$

Tauwehe

$$\left(b-3\right)^{2}$$

Ngā Upane Otinga

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei b^{2}+pb+qb+9. Hei kimi p me q, whakaritea tētahi pūnaha kia whakaoti.

$$p+q=-6 pq=1\times 9=9$$

I te mea kua tōrunga te pq, he ōrite te tohu o p me q. I te mea kua tōraro te p+q, he tōraro hoki a p me q. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 9.

$$-1,-9 -3,-3$$

Tātaihia te tapeke mō ia takirua.

$$-1-9=-10 -3-3=-6$$

Ko te otinga te takirua ka hoatu i te tapeke -6.

$$p=-3 q=-3$$

Tuhia anō te b^{2}-6b+9 hei \left(b^{2}-3b\right)+\left(-3b+9\right).

$$\left(b^{2}-3b\right)+\left(-3b+9\right)$$

Tauwehea te b i te tuatahi me te -3 i te rōpū tuarua.

$$b\left(b-3\right)-3\left(b-3\right)$$

Whakatauwehea atu te kīanga pātahi b-3 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(b-3\right)\left(b-3\right)$$

Tuhia anōtia hei pūrua huarua.

$$\left(b-3\right)^{2}$$

Ngā Upane Whakamahi Tauwehe o te Pūrua Huarua

Ko te tikanga tātai o tēnei huatoru he pūrua huatoru, ka whakareatia pea e tētahi tauwehe pātahi. Ka taea ngā pūrua huatoru te tauwehe mā te kimi i ngā pūtakerua o ngā kīanga tau ārahi, autō hoki.

$$factor(b^{2}-6b+9)$$

Kimihia te pūtakerua o te kīanga tau autō, 9.

$$\sqrt{9}=3$$

Ko te pūrua huatoru te pūrua o te huarua ko te tapeke tērā, te huatango rānei o ngā pūtakerua o ngā kīanga tau ārahi, autō hoki, e whakaritea ai te tohu e te tohu o te kīanga tau waenga o te pūrua huatoru.

$$\left(b-3\right)^{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$b^{2}-6b+9=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$b=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\times 9}}{2}$$

Pūrua -6.

$$b=\frac{-\left(-6\right)±\sqrt{36-4\times 9}}{2}$$

Whakareatia -4 ki te 9.

$$b=\frac{-\left(-6\right)±\sqrt{36-36}}{2}$$

Tāpiri 36 ki te -36.

$$b=\frac{-\left(-6\right)±\sqrt{0}}{2}$$

Tuhia te pūtakerua o te 0.

$$b=\frac{-\left(-6\right)±0}{2}$$

Ko te tauaro o -6 ko 6.

$$b=\frac{6±0}{2}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 3 mō te x_{1} me te 3 mō te x_{2}.

$$b^{2}-6b+9=\left(b-3\right)\left(b-3\right)$$

Aromātai

$$\left(b-3\right)^{2}$$