Whakaoti i te b^2-4ac=3

$$b ^ { 2 } - 4 a c = 3$$

Whakaoti mō a (complex solution)

$$\left\{\begin{matrix}a=\frac{b^{2}-3}{4c}\text{, }&c\neq 0\\a\in \mathrm{C}\text{, }&\left(b=\sqrt{3}\text{ or }b=-\sqrt{3}\right)\text{ and }c=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te b^{2} mai i ngā taha e rua.

$$-4ac=3-b^{2}$$

He hanga arowhānui tō te whārite.

$$\left(-4c\right)a=3-b^{2}$$

Whakawehea ngā taha e rua ki te -4c.

$$\frac{\left(-4c\right)a}{-4c}=\frac{3-b^{2}}{-4c}$$

Mā te whakawehe ki te -4c ka wetekia te whakareanga ki te -4c.

$$a=\frac{3-b^{2}}{-4c}$$

Whakawehe -b^{2}+3 ki te -4c.

$$a=-\frac{3-b^{2}}{4c}$$

Whakaoti mō a

$$\left\{\begin{matrix}a=\frac{b^{2}-3}{4c}\text{, }&c\neq 0\\a\in \mathrm{R}\text{, }&c=0\text{ and }|b|=\sqrt{3}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te b^{2} mai i ngā taha e rua.

$$-4ac=3-b^{2}$$

He hanga arowhānui tō te whārite.

$$\left(-4c\right)a=3-b^{2}$$

Whakawehea ngā taha e rua ki te -4c.

$$\frac{\left(-4c\right)a}{-4c}=\frac{3-b^{2}}{-4c}$$

Mā te whakawehe ki te -4c ka wetekia te whakareanga ki te -4c.

$$a=\frac{3-b^{2}}{-4c}$$

Whakawehe 3-b^{2} ki te -4c.

$$a=-\frac{3-b^{2}}{4c}$$

Whakaoti mō b (complex solution)

$$b=-\sqrt{4ac+3}$$

$$b=\sqrt{4ac+3}$$

Whakaoti mō b

$$b=\sqrt{4ac+3}$$

$$b=-\sqrt{4ac+3}\text{, }\left(c\leq 0\text{ or }a\geq -\frac{3}{4c}\right)\text{ and }\left(c\geq 0\text{ or }a\leq -\frac{3}{4c}\right)$$