Whakaoti i te b=25ya-b

$$b = 25 y a - b$$

Whakaoti mō a (complex solution)

$$\left\{\begin{matrix}a=\frac{2b}{25y}\text{, }&y\neq 0\\a\in \mathrm{C}\text{, }&b=0\text{ and }y=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$25ya-b=b$$

Me tāpiri te b ki ngā taha e rua.

$$25ya=b+b$$

Pahekotia te b me b, ka 2b.

$$25ya=2b$$

Whakawehea ngā taha e rua ki te 25y.

$$\frac{25ya}{25y}=\frac{2b}{25y}$$

Mā te whakawehe ki te 25y ka wetekia te whakareanga ki te 25y.

$$a=\frac{2b}{25y}$$

Whakaoti mō a

$$\left\{\begin{matrix}a=\frac{2b}{25y}\text{, }&y\neq 0\\a\in \mathrm{R}\text{, }&b=0\text{ and }y=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$25ya-b=b$$

Me tāpiri te b ki ngā taha e rua.

$$25ya=b+b$$

Pahekotia te b me b, ka 2b.

$$25ya=2b$$

Whakawehea ngā taha e rua ki te 25y.

$$\frac{25ya}{25y}=\frac{2b}{25y}$$

Mā te whakawehe ki te 25y ka wetekia te whakareanga ki te 25y.

$$a=\frac{2b}{25y}$$

Whakaoti mō b

$$b=\frac{25ay}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te b ki ngā taha e rua.

$$b+b=25ya$$

Pahekotia te b me b, ka 2b.

$$2b=25ya$$

He hanga arowhānui tō te whārite.

$$2b=25ay$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2b}{2}=\frac{25ay}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$b=\frac{25ay}{2}$$