Whakaoti i te ax^2+(a+2)x+1=0

$$a x ^ { 2 } + ( a + 2 ) x + 1 = 0$$

Whakaoti mō a

$$a=-\frac{2x+1}{x\left(x+1\right)}$$

$$x\neq -1\text{ and }x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a+2 ki te x.

$$ax^{2}+ax+2x+1=0$$

Tangohia te 2x mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$ax^{2}+ax+1=-2x$$

Tangohia te 1 mai i ngā taha e rua.

$$ax^{2}+ax=-2x-1$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(x^{2}+x\right)a=-2x-1$$

Whakawehea ngā taha e rua ki te x^{2}+x.

$$\frac{\left(x^{2}+x\right)a}{x^{2}+x}=\frac{-2x-1}{x^{2}+x}$$

Mā te whakawehe ki te x^{2}+x ka wetekia te whakareanga ki te x^{2}+x.

$$a=\frac{-2x-1}{x^{2}+x}$$

Whakawehe -2x-1 ki te x^{2}+x.

$$a=-\frac{2x+1}{x\left(x+1\right)}$$

Whakaoti mō x

$$\left\{\begin{matrix}x=\frac{\sqrt{a^{2}+4}-a-2}{2a}\text{; }x=-\frac{\sqrt{a^{2}+4}+a+2}{2a}\text{, }&a\neq 0\\x=-\frac{1}{2}\text{, }&a=0\end{matrix}\right.$$