Whakaoti i te aab=1(1-6)+(2-5)

$$a a b = 1 ( 1 - 6 ) + ( 2 - 5 )$$

Whakaoti mō b

$$b=-\frac{8}{a^{2}}$$

$$a\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te a ki te a, ka a^{2}.

$$a^{2}b=1\left(1-6\right)+2-5$$

Tangohia te 6 i te 1, ka -5.

$$a^{2}b=1\left(-5\right)+2-5$$

Whakareatia te 1 ki te -5, ka -5.

$$a^{2}b=-5+2-5$$

Tāpirihia te -5 ki te 2, ka -3.

$$a^{2}b=-3-5$$

Tangohia te 5 i te -3, ka -8.

$$a^{2}b=-8$$

Whakawehea ngā taha e rua ki te a^{2}.

$$\frac{a^{2}b}{a^{2}}=-\frac{8}{a^{2}}$$

Mā te whakawehe ki te a^{2} ka wetekia te whakareanga ki te a^{2}.

$$b=-\frac{8}{a^{2}}$$

Whakaoti mō a (complex solution)

$$a=-2\sqrt{2}ib^{-\frac{1}{2}}$$

$$a=2\sqrt{2}ib^{-\frac{1}{2}}\text{, }b\neq 0$$

Whakaoti mō a

$$a=2\sqrt{-\frac{2}{b}}$$

$$a=-2\sqrt{-\frac{2}{b}}\text{, }b<0$$