Whakaoti i te a(x+a)-x=a(a+1)+1

$$a ( x + a ) - x = a ( a + 1 ) + 1$$

Whakaoti mō a

$$a=\frac{x+1}{x-1}$$

$$x\neq 1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te x+a.

$$ax+a^{2}-x=a\left(a+1\right)+1$$

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te a+1.

$$ax+a^{2}-x=a^{2}+a+1$$

Tangohia te a^{2} mai i ngā taha e rua.

$$ax+a^{2}-x-a^{2}=a+1$$

Pahekotia te a^{2} me -a^{2}, ka 0.

$$ax-x=a+1$$

Tangohia te a mai i ngā taha e rua.

$$ax-x-a=1$$

Me tāpiri te x ki ngā taha e rua.

$$ax-a=1+x$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(x-1\right)a=1+x$$

He hanga arowhānui tō te whārite.

$$\left(x-1\right)a=x+1$$

Whakawehea ngā taha e rua ki te x-1.

$$\frac{\left(x-1\right)a}{x-1}=\frac{x+1}{x-1}$$

Mā te whakawehe ki te x-1 ka wetekia te whakareanga ki te x-1.

$$a=\frac{x+1}{x-1}$$

Whakaoti mō x

$$x=\frac{a+1}{a-1}$$

$$a\neq 1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te x+a.

$$ax+a^{2}-x=a\left(a+1\right)+1$$

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te a+1.

$$ax+a^{2}-x=a^{2}+a+1$$

Tangohia te a^{2} mai i ngā taha e rua.

$$ax-x=a^{2}+a+1-a^{2}$$

Pahekotia te a^{2} me -a^{2}, ka 0.

$$ax-x=a+1$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(a-1\right)x=a+1$$

Whakawehea ngā taha e rua ki te -1+a.

$$\frac{\left(a-1\right)x}{a-1}=\frac{a+1}{a-1}$$

Mā te whakawehe ki te -1+a ka wetekia te whakareanga ki te -1+a.

$$x=\frac{a+1}{a-1}$$