Whakaoti i te a(-63)+beta(3-9)=c-2

$$a ( - 63 ) + \beta ( 3 - 9 ) = c - 2$$

Whakaoti mō a

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 9 i te 3, ka -6.

$$a\left(-63\right)+\beta \left(-6\right)=c-2$$

Tangohia te \beta \left(-6\right) mai i ngā taha e rua.

$$a\left(-63\right)=c-2-\beta \left(-6\right)$$

Whakareatia te -1 ki te -6, ka 6.

$$a\left(-63\right)=c-2+6\beta$$

He hanga arowhānui tō te whārite.

$$-63a=c+6\beta -2$$

Whakawehea ngā taha e rua ki te -63.

$$\frac{-63a}{-63}=\frac{c+6\beta -2}{-63}$$

Mā te whakawehe ki te -63 ka wetekia te whakareanga ki te -63.

$$a=\frac{c+6\beta -2}{-63}$$

Whakawehe c-2+6\beta ki te -63.

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Whakaoti mō c

$$c=2-6\beta -63a$$