Whakaoti i te a(-6.3)+beta(3.-9)=c-2

$$a ( - 6.3 ) + \beta ( 3 . - 9 ) = c - 2$$

Whakaoti mō a

$$a=-\frac{10c}{63}-\frac{20\beta }{21}+\frac{20}{63}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 9 i te 3, ka -6.

$$a\left(-6.3\right)+\beta \left(-6\right)=c-2$$

Tangohia te \beta \left(-6\right) mai i ngā taha e rua.

$$a\left(-6.3\right)=c-2-\beta \left(-6\right)$$

Whakareatia te -1 ki te -6, ka 6.

$$a\left(-6.3\right)=c-2+6\beta$$

He hanga arowhānui tō te whārite.

$$-6.3a=c+6\beta -2$$

Whakawehea ngā taha e rua o te whārite ki te -6.3, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{-6.3a}{-6.3}=\frac{c+6\beta -2}{-6.3}$$

Mā te whakawehe ki te -6.3 ka wetekia te whakareanga ki te -6.3.

$$a=\frac{c+6\beta -2}{-6.3}$$

Whakawehe c-2+6\beta ki te -6.3 mā te whakarea c-2+6\beta ki te tau huripoki o -6.3.

$$a=-\frac{10c}{63}-\frac{20\beta }{21}+\frac{20}{63}$$

Whakaoti mō c

$$c=-\frac{63a}{10}-6\beta +2$$