Whakaoti i te a^6-a^4+a^2-1=

$$a ^ { 6 } - a ^ { 4 } + a ^ { 2 } - 1 =$$

Tauwehe

$$\left(a-1\right)\left(a+1\right)\left(a^{4}+1\right)$$

Ngā Upane Otinga

Mahia te whakarōpūtanga a^{6}-a^{4}+a^{2}-1=\left(a^{6}-a^{4}\right)+\left(a^{2}-1\right), ka whakatauwehea atu a^{4} i te a^{6}-a^{4}.

$$a^{4}\left(a^{2}-1\right)+a^{2}-1$$

Whakatauwehea atu te kīanga pātahi a^{2}-1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(a^{2}-1\right)\left(a^{4}+1\right)$$

Whakaarohia te a^{2}-1. Tuhia anō te a^{2}-1 hei a^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).

$$\left(a-1\right)\left(a+1\right)$$

Me tuhi anō te kīanga whakatauwehe katoa. Kāore te pūrau a^{4}+1 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$\left(a-1\right)\left(a+1\right)\left(a^{4}+1\right)$$

Aromātai

$$\left(a^{2}-1\right)\left(a^{4}+1\right)$$